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The sum of the factors of x^3 + 8x^2 + 19x + 12 is

Factoring the cubic polynomial gives \(x^3 + 8x^2 + 19x + 12 = (x + 1)(x + 3)(x + 4)\). The sum of its linear factors is \((x + 1) + (x + 3) + (x + 4) = 3x + 8\).

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The sum of the factors of x^3 + 8x^2 + 19x + 12 is

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Factoring the cubic polynomial gives x3+8x2+19x+12=(x+1)(x+3)(x+4)x^3 + 8x^2 + 19x + 12 = (x + 1)(x + 3)(x + 4). The sum of its linear factors is (x+1)+(x+3)+(x+4)=3x+8(x + 1) + (x + 3) + (x + 4) = 3x + 8.

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  • Rajasthan Clerk Grade 2

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