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The sum of the ages of father and son is 45 years. Five years ago the product of their ages was 4 times…

The correct choice is: 36 yrs, 9 yrs Five years ago: \((F-5)(S-5)=4(F-5)\), so \(S-5=4\), i.e. \(S=9\). Then \(F=45-9=36\). Hence the ages are 36 yrs, 9 yrs.

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The sum of the ages of father and son is 45 years. Five years ago the product of their ages was 4 times the father's age at that time. The present ages of the father and son, respectively are:

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Correct answer B

The correct choice is: 36 yrs, 9 yrs

Five years ago: (F−5)(S−5)=4(F−5)(F-5)(S-5)=4(F-5), so S−5=4S-5=4, i.e. S=9S=9.

Then F=45−9=36F=45-9=36.

Hence the ages are 36 yrs, 9 yrs.

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