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The simple interest on a sum of money is \( \frac{4}{9} \) of the principal. If rate percent and time…

\(\text{S.I.}=\frac{PRT}{100}=\frac49P\) with \(R=T\), so \(\frac{R^2}{100}=\frac49\). Then \(R^2=\frac{400}{9}\) and \(R=\frac{20}{3}=6\tfrac23\%\), with the time also…

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The simple interest on a sum of money is 49 \frac{4}{9} of the principal. If rate percent and time are numerically equal then find the rate percent

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Correct answer D

S.I.=PRT100=49P\text{S.I.}=\frac{PRT}{100}=\frac49P with R=TR=T, so R2100=49\frac{R^2}{100}=\frac49. Then R2=4009R^2=\frac{400}{9} and R=203=623%R=\frac{20}{3}=6\tfrac23\%, with the time also 6236\tfrac23 years. Check: 203×203÷100=400900=49\frac{20}{3}\times\frac{20}{3}\div100=\frac{400}{900}=\frac49. A rate of 823%8\tfrac23\% would make the interest 676900\frac{676}{900} of the principal, far more than 49=400900\frac49=\frac{400}{900}.

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