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The product of the ages of Sagun and Srishti is 240. If twice the age of Srishti is more than Sagun’s…

Let Srishti's age be \(s\), so Sagun's age is \(2s-4\) and \(s(2s-4)=240\). This gives \(s^2-2s-120=0\), that is \((s-12)(s+10)=0\), so \(s=12\). Srishti is 12 and Sagun is…

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The product of the ages of Sagun and Srishti is 240. If twice the age of Srishti is more than Sagun’s age by 4 years, then what is Srishti’s age?

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Correct answer B

Let Srishti's age be ss, so Sagun's age is 2s−42s-4 and s(2s−4)=240s(2s-4)=240. This gives s2−2s−120=0s^2-2s-120=0, that is (s−12)(s+10)=0(s-12)(s+10)=0, so s=12s=12. Srishti is 12 and Sagun is 20, and their product is indeed 240.

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