The probability that a randomly chosen positive divisor of \(10 ^ {2023}\) is an integer multiple of \(10 ^ {2001}\) is
Question and options
The probability that a randomly chosen positive divisor of is an integer multiple of is
Answer and explanation
Correct answer: B - \(\dfrac{23^2}{{2024}^2}\)
10^2023 = 2^2023 5^2023 has 2024^2 divisors. Multiples of 10^2001 need both exponents in 2001..2023: 23 choices each, 23^2. Probability 23^2/2024^2.
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