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The number of real solutions of the equation \((x^2 - 15x + 55)^{x^2-5x+6} = 1\) is:

Question and options

The number of real solutions of the equation (x2−15x+55)x2−5x+6=1(x^2 - 15x + 55)^{x^2-5x+6} = 1 is:
  1. 0
  2. 2
  3. 6
  4. 4

Answer and explanation

Correct answer: C - 6

The equation has 6 real solutions. A zero exponent gives x=2,3x=2,3, while a base of 1 gives x=6,9x=6,9. A base of −1-1 gives x=7,8x=7,8, where the exponents are the even integers 20 and 30, respectively. Counting 4 solutions omits these last two cases.

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  • IPMAT Indore

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