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The number of optical isomers of \(\mathrm{CH_3CH(OH)CH(OH)CHO}\) is

Question and options

The number of optical isomers of CH3CH(OH)CH(OH)CHO\mathrm{CH_3CH(OH)CH(OH)CHO} is
  1. zero
  2. 2
  3. 3
  4. 4

Answer and explanation

Correct answer: D - 4
CH3−CH(OH)−CH(OH)−CHO\mathrm{CH_3{-}CH(OH){-}CH(OH){-}CHO} has two different chiral centres (C2 and C3) and no symmetry, so 22=42^2 = 4 optical isomers.

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