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The minute hand of a watch is 42 mm long. Taking π as 3.14, the area (in mm2) swept by it in 30 minutes…

The area swept is about 2769.5 mm2. In 30 minutes the minute hand turns through half a circle, so it sweeps \(\frac{1}{2}\pi r^{2}\) \(= \frac{1}{2} \times 3.14 \times…

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The minute hand of a watch is 42 mm long. Taking π as 3.14, the area (in mm2) swept by it in 30 minutes is:

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Correct answer A

The area swept is about 2769.5 mm2. In 30 minutes the minute hand turns through half a circle, so it sweeps 12πr2\frac{1}{2}\pi r^{2} =12×3.14×422= \frac{1}{2} \times 3.14 \times 42^{2} =12×3.14×1764= \frac{1}{2} \times 3.14 \times 1764 ≈2769.5\approx 2769.5 mm2. 44π44\pi (about 138) and 728 are far too small, and 1040π1040\pi (about 3266) is larger than the half-circle area.

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