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The HCF of \((\frac{9}{10}, \frac{12}{25}, \frac{18}{35}, \frac{21}{40})\) is

Question and options

The HCF of (910,1225,1835,2140)(\frac{9}{10}, \frac{12}{25}, \frac{18}{35}, \frac{21}{40}) is
  1. 35\frac{3}{5}
  2. 2525\frac{252}{5}
  3. 63700\frac{63}{700}
  4. 31400\frac{3}{1400}

Answer and explanation

Correct answer: D - \(\frac{3}{1400}\)
HCF of fractions = HCF of numerators / LCM of denominators. HCF(9,12,18,21) = 3 and LCM(10,25,35,40) = 1400, giving 3/1400.

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