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The frequency of strong yellow line in the spectrum of sodium is \(5.09 \times 10^{14}\ \mathrm{s^{-1}}\). What will be the wavelength in nanometres? (Given \(c = 3.0 \times 10^{8}\ \mathrm{m/sec}\))

Question and options

The frequency of strong yellow line in the spectrum of sodium is 5.09×1014 s−15.09 \times 10^{14}\ \mathrm{s^{-1}}. What will be the wavelength in nanometres? (Given c=3.0×108 m/secc = 3.0 \times 10^{8}\ \mathrm{m/sec})
  1. 589.4 nm
  2. 400 nm
  3. 766.5 nm
  4. 58.94 nm

Answer and explanation

Correct answer: A - 589.4 nm
λ=cν=3.0×108 m/s5.09×1014 s−1=5.894×10−7 m=589.4 nm\lambda = \frac{c}{\nu} = \frac{3.0 \times 10^{8}\ \mathrm{m/s}}{5.09 \times 10^{14}\ \mathrm{s^{-1}}} = 5.894 \times 10^{-7}\ \mathrm{m} = 589.4\ \mathrm{nm}.

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