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The freezing temperature of pure water is

Question and options

The freezing temperature of pure water is
  1. 32 ∘F32\ ^\circ\mathrm{F}
  2. 32 ∘C32\ ^\circ\mathrm{C}
  3. 49 ∘F49\ ^\circ\mathrm{F}
  4. 0 ∘F0\ ^\circ\mathrm{F}

Answer and explanation

Correct answer: A - \(32\ ^\circ\mathrm{F}\)
Pure water freezes at 0 ∘C0\ ^\circ\mathrm{C}, which equals 32 ∘F32\ ^\circ\mathrm{F} (F=95×0+32F = \frac{9}{5} \times 0 + 32).

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