The free-ion ground-state spectroscopic term symbol of the metal ion in \(\mathrm{[Ti(H_2O)_6]^{2+}}\) is

In $\mathrm{[Ti(H_2O)_6]^{2+}}$, the central metal ion is $\mathrm{Ti^{2+}}$ ($3d^2$). For the free $d^2$ ion, Hund's rules give $S = 1$ (multiplicity $2S+1 = 3$), $L = 2 + 1 = 3$ (F), and $J = L - S = 2$ (less than half-filled subshell), so the free-ion ground-state Russell–Saunders term symbol is ${}^{3}\mathrm{F}_{2}$ (which splits in an octahedral field to give a ${}^{3}\mathrm{T}_{1g}$ ground term).