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The equation of the straight line passing through the point \(M (-5,4)\), such that the portion of it between the axes is divided by the point \(M\) into two equal halves, is

Question and options

The equation of the straight line passing through the point M(−5,4)M (-5,4), such that the portion of it between the axes is divided by the point MM into two equal halves, is
  1. 10y−8x=8010y - 8x = 80
  2. 8y+10x=808y + 10x = 80
  3. 10y+8x=8010y + 8x = 80
  4. 8y+10x+80=08y + 10x + 80 = 0

Answer and explanation

Correct answer: A - \(10y - 8x = 80\)
M is the midpoint of the intercepts, so intercepts are (-10,0) and (0,8). Line x/(-10)+y/8=1, i.e. 10y-8x=80. Check: 10*4-8*(-5)=80.

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  • IPMAT Indore

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