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The diameter of a wheel of a heavy load vehicle is \(\frac{7}{2}\) feet. If the wheel makes 26…

The sum is approximately 298. The circumference is \(7\pi/2\) feet, so \(x=26(7\pi/2)=91\pi\) and \(y\) \(=132/(7\pi/2)\) \(=264/(7\pi)\). Thus \(x+y\) \(=91\pi+264/(7\pi)\)…

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The diameter of a wheel of a heavy load vehicle is 72\frac{7}{2} feet. If the wheel makes 26 revolutions the vehicle moves a distance x feet. If the vehicle moves 132 feet, the wheel makes y revolutions. The sum of numerical values of x and y is approximately

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The sum is approximately 298. The circumference is 7π/27\pi/2 feet, so x=26(7π/2)=91πx=26(7\pi/2)=91\pi and yy =132/(7π/2)=132/(7\pi/2) =264/(7π)=264/(7\pi). Thus x+yx+y =91π+264/(7π)=91\pi+264/(7\pi) ≈297.89\approx297.89, which rounds to 298.

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