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The concentration of the solution of tryptophan that has an absorbance of 0.54 at 280 nm in a 0.5 cm length cuvette (the absorbance coefficient of tryptophan is \(6.01 \times 10^3\ \mathrm{L\…

Question and options

The concentration of the solution of tryptophan that has an absorbance of 0.54 at 280 nm in a 0.5 cm length cuvette (the absorbance coefficient of tryptophan is 6.01×103 L mol−1 cm−16.01 \times 10^3\ \mathrm{L\ mol^{-1}\ cm^{-1}}) is
  1. 0.000166 M
  2. 0.166 M
  3. 0.006 M
  4. None of the given options is correct

Answer and explanation

Correct answer: D - None of the given options is correct
Beer-Lambert law: c=Aεl=0.546.01×103×0.5=1.80×10−4 Mc = \frac{A}{\varepsilon l} = \frac{0.54}{6.01 \times 10^3 \times 0.5} = 1.80 \times 10^{-4}\ \mathrm{M}, that is 0.00018 M. This matches none of the numerical values offered: 0.000166 M would need an absorbance of 0.5, and 0.166 M and 0.006 M are far off.

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