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The average age of a family of six members is 30 years. The youngest members of the family are twins…

The present total age of the six members is \(6\times30=180\) years. Removing the twins aged 10 each leaves \(180-20=160\) years for the other four members, and ten years…

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The average age of a family of six members is 30 years. The youngest members of the family are twins with age 10 years. Find the average age of the family just before the birth of the twins.

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Correct answer C

The present total age of the six members is 6×30=1806\times30=180 years. Removing the twins aged 10 each leaves 180−20=160180-20=160 years for the other four members, and ten years ago their total was 160−40=120160-40=120 years. The average just before the twins were born was 1204=30\frac{120}{4}=30 years.

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