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The average age of a committee of 10 members is 42 years. A member of age 53 retires and a new member…

The present total age is \(10 \times 42 = 420\) years. Removing the member aged 53 and adding one aged 45 changes the total to \(420 - 53 + 45 = 412\). The new average is…

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The average age of a committee of 10 members is 42 years. A member of age 53 retires and a new member of age 45 years takes his place. What is the average age of the new committee?

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The present total age is 10×42=42010 \times 42 = 420 years. Removing the member aged 53 and adding one aged 45 changes the total to 420−53+45=412420 - 53 + 45 = 412. The new average is 41210=41.2\frac{412}{10} = 41.2 years.

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