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The ages of two sisters A and B are in the ratio of 7:6. After 12 years, the ratio of their ages will…

Let the ages be \(7x\) and \(6x\). Then \(\frac{7x+12}{6x+12}=\frac{9}{8}\) gives \(56x+96=54x+108\), so \(x=6\). The ages are 42 and 36 and the difference is 6 years.

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The ages of two sisters A and B are in the ratio of 7:6. After 12 years, the ratio of their ages will be 9:8. Find the difference between their ages.

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Correct answer C

Let the ages be 7x7x and 6x6x. Then 7x+126x+12=98\frac{7x+12}{6x+12}=\frac{9}{8} gives 56x+96=54x+10856x+96=54x+108, so x=6x=6. The ages are 42 and 36 and the difference is 6 years.

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