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Ten years ago, the ratio of ages of A and B was 3 : 5. The ratio of their present ages is 2 : 3. Their…

The correct choice is: 40, 60 Let the present ages be \(2k\) and \(3k\). Ten years ago: \(\dfrac{2k-10}{3k-10}=\dfrac35\). \(10k-50=9k-30\Rightarrow k=20\), so the ages are…

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Ten years ago, the ratio of ages of A and B was 3 : 5. The ratio of their present ages is 2 : 3. Their respective ages in years are:

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Correct answer D

The correct choice is: 40, 60

Let the present ages be 2k2k and 3k3k. Ten years ago: 2k−103k−10=35\dfrac{2k-10}{3k-10}=\dfrac35.

10k−50=9k−30⇒k=2010k-50=9k-30\Rightarrow k=20, so the ages are 40 and 60. (Check: 30 : 50 = 3 : 5.)

Hence the answer is 40, 60.

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