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Ratio of the volumes of two cones is 4:25 and their heights are in the ratio 25:64, then the ratio of…

The volume of a cone is \(V = \frac{1}{3}\pi r^2 h\). Thus \(\frac{V_1}{V_2} = \left(\frac{r_1}{r_2}\right)^2 \left(\frac{h_1}{h_2}\right) \implies \frac{4}{25} =…

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Ratio of the volumes of two cones is 4:25 and their heights are in the ratio 25:64, then the ratio of the radius of their base is -

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The volume of a cone is V=13πr2hV = \frac{1}{3}\pi r^2 h. Thus V1V2=(r1r2)2(h1h2)  ⟹  425=(r1r2)2×2564  ⟹  (r1r2)2=4×6425×25  ⟹  r1r2=2×85×5=1625\frac{V_1}{V_2} = \left(\frac{r_1}{r_2}\right)^2 \left(\frac{h_1}{h_2}\right) \implies \frac{4}{25} = \left(\frac{r_1}{r_2}\right)^2 \times \frac{25}{64} \implies \left(\frac{r_1}{r_2}\right)^2 = \frac{4 \times 64}{25 \times 25} \implies \frac{r_1}{r_2} = \frac{2 \times 8}{5 \times 5} = \frac{16}{25}.

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