Of the 120 people in the room, \(\frac{3}{5}\) are women. If \(\frac{2}{3}\) of the people are married, then what is the maximum number of women in the room who could be unmarried?

Question and options

Of the 120 people in the room,

\frac{3}{5}

are women. If

\frac{2}{3}

of the people are married, then what is the maximum number of women in the room who could be unmarried?

Correct answer: A - 40

Women =

\frac{3}{5} \times 120 = 72

; married people =

\frac{2}{3} \times 120 = 80

, so unmarried = 40. At most all 40 unmarried people can be women, so the maximum is 40.