Match the LIST-I with LIST-II If 10% of S = 12% of T, then match the following : LIST-ILIST-II A. x as…
Given that 10% of S = 12% of T, we have S = 1.2T and equivalently T = (5/6)S. Substituting these relations: for A, 15% of S = 15 × 1.2% of T = 18% of T, so x = 18 (IV); for…
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Match the LIST-I with LIST-II
If 10% of S = 12% of T, then match the following :
| LIST-I | LIST-II | ||
|---|---|---|---|
| A. | x as in 15% of S = x% of T | I. | 25 |
| B. | y as in 25% of S = y% of T | II. | 12.5 |
| C. | z as in 15% of T = z% of S | III. | 30 |
| D. | p as in 30% of T = p% of S | IV. | 18 |
Answer and explanation
Correct answer D
Given that 10% of S = 12% of T, we have S = 1.2T and equivalently T = (5/6)S. Substituting these relations: for A, 15% of S = 15 × 1.2% of T = 18% of T, so x = 18 (IV); for B, 25% of S = 25 × 1.2% of T = 30% of T, so y = 30 (III); for C, 15% of T = 15 × (5/6)% of S = 12.5% of S, so z = 12.5 (II); and for D, 30% of T = 30 × (5/6)% of S = 25% of S, so p = 25 (I). Hence, the correct matching is A-IV, B-III, C-II, D-I.
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