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Let \(S_n\) be sum of the first \(n\) terms of an A.P. If \(S_5 = S_9\), what is the ratio of \(a_3 : a_5\)

Question and options

Let SnS_n be sum of the first nn terms of an A.P. If S5=S9S_5 = S_9, what is the ratio of a3:a5a_3 : a_5
  1. 9:59:5
  2. 5:95:9
  3. 3:53:5
  4. 5:35:3

Answer and explanation

Correct answer: A - \(9:5\)
S5=5(a+2d), S9=9(a+4d). Equating: 5a+10d=9a+36d -> a=-6.5d. a3=a+2d=-4.5d, a5=a+4d=-2.5d, so a3:a5 = 9:5.

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