Let \(S = \{1, 2, \ldots, 180\}\). Define \(A\) as the set of all multiples of 4 in \(S\), \(B\) as the set of all multiples of 6 in \(S\), and \(C\) as the set of all multiples of 9 in \(S\). The…
Question and options
Let . Define as the set of all multiples of 4 in , as the set of all multiples of 6 in , and as the set of all multiples of 9 in . The number of elements in that belong to exactly one of is
- 50
- 40
- 48
- 44
Answer and explanation
Correct answer: A - 50
|A|=45, |B|=30, |C|=20, |A^B| (mult of 12)=15, |A^C| (36)=5, |B^C| (18)=10, |A^B^C| (36)=5. Exactly one = sum singles - 2*sum pairs + 3*triple = 95 - 60 + 15 = 50.
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IPMAT Indore
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