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Let \(S_1 = \{100, 105, 110, 115, ... \}\) and \(S_2 = \{100, 95, 90, 85, ... \}\) be two series in arithmetic progression. If \(a_k\) and \(b_k\) are the \(k\)-th terms of \(S_1\) and \(S_2\),…

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Let S1={100,105,110,115,...}S_1 = \{100, 105, 110, 115, ... \} and S2={100,95,90,85,...}S_2 = \{100, 95, 90, 85, ... \} be two series in arithmetic progression. If aka_k and bkb_k are the kk-th terms of S1S_1 and S2S_2, respectively, then ∑k=120akbk\sum_{k=1}^{20} a_k b_k equals __________.
  1. 137275
  2. 138250
  3. 137225
  4. 135375

Answer and explanation

Correct answer: B - 138250
a_k b_k = (100+5j)(100-5j) = 10000 - 25j^2 for j = 0..19. Sum = 200000 - 25*2470 = 138250.

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