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Let \(M = \begin{bmatrix} 1 & 1 & 1 \\ a & b & c \\ a^2 & b^2 & c^2 \end{bmatrix}\) where \(a, b\) and \(c\) are real numbers such that \(a + b + c = 0\) and \(abc \neq 0\). If \(\det M = 0\), then…

Question and options

Let M=[111abca2b2c2]M = \begin{bmatrix} 1 & 1 & 1 \\ a & b & c \\ a^2 & b^2 & c^2 \end{bmatrix} where a,ba, b and cc are real numbers such that a+b+c=0a + b + c = 0 and abc≠0abc \neq 0. If det⁡M=0\det M = 0, then the maximum possible value of a2+b2c2\frac{a^2+b^2}{c^2} is __________
  1. 1
  2. 5
  3. 4
  4. 2

Answer and explanation

Correct answer: B - 5

The maximum is 55. The determinant equals (b−a)(c−a)(c−b)(b-a)(c-a)(c-b), so at least two variables coincide. If a=ba=b, then c=−2ac=-2a and the ratio is 12\frac12, and if a=ca=c or b=cb=c, the remaining variable is −2c-2c and the ratio is 55. The value 44 comes from dropping the smaller squared term in the latter cases.

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