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Let \(\alpha, \beta\) be the roots of \(x^2 - x + p = 0\) and \(\gamma, \delta\) be the roots of \(x^2 - 4x + q = 0\) where p and q are integers. If \(\alpha, \beta, \gamma, \delta\) are in…

Question and options

Let α,β\alpha, \beta be the roots of x2−x+p=0x^2 - x + p = 0 and γ,δ\gamma, \delta be the roots of x2−4x+q=0x^2 - 4x + q = 0 where p and q are integers. If α,β,γ,δ\alpha, \beta, \gamma, \delta are in geometric progression then p+qp + q is
  1. -34
  2. 30
  3. 26
  4. -38

Answer and explanation

Correct answer: A - -34
Let terms be t, tr, tr^2, tr^3: t(1+r) = 1 and tr^2(1+r) = 4 so r = +-2. r = 2 gives p = 2/9 (not integer); r = -2 gives t = -1, p = t^2 r = -2, q = t^2 r^5 = -32, p+q = -34.

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