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Let \(a = \dfrac{(\log_7 4)(\log_7 5 - \log_7 2)}{\log_{7} 25 (\log_7 8 - \log_7 4)}\). Then the value of \(5^a\) is

Question and options

Let a=(log⁡74)(log⁡75−log⁡72)log⁡725(log⁡78−log⁡74)a = \dfrac{(\log_7 4)(\log_7 5 - \log_7 2)}{\log_{7} 25 (\log_7 8 - \log_7 4)}. Then the value of 5a5^a is
  1. 8
  2. 52\frac{5}{2}
  3. 5
  4. 72\frac{7}{2}

Answer and explanation

Correct answer: B - \(\frac{5}{2}\)
Numerator = 2log7(2)*log7(5/2); denominator = 2log7(5)*log7(2). So a = log7(5/2)/log7(5) = log5(5/2), hence 5^a = 5/2.

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  • IPMAT Indore

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