Site navigation

Let \(a, b, c\) be real numbers greater than 1, and \(n\) be a positive real number not equal to 1. If \(log_n(log_2a) = 1; log_n(log_2b) = 2\) and \(log_n(log_2c) = 3\) then which of the following…

Question and options

Let a,b,ca, b, c be real numbers greater than 1, and nn be a positive real number not equal to 1. If logn(log2a)=1;logn(log2b)=2log_n(log_2a) = 1; log_n(log_2b) = 2 and logn(log2c)=3log_n(log_2c) = 3 then which of the following is true?
  1. (b−a)n=(c−b)(b-a)^n=(c-b)
  2. an+bn=cna^n+b^n=c^n
  3. a+b=ca+b=c
  4. (an+b)n=ac(a^n+b)^n=ac

Answer and explanation

Correct answer: D - \((a^n+b)^n=ac\)
log2 a = n, log2 b = n^2, log2 c = n^3, so a=2^n, b=2^(n^2)=a^n, c=2^(n^3). Then (a^n+b)^n = (2b)^n = 2^n * 2^(n^3) = a*c.

Practice for these exams

  • IPMAT Indore

Related question papers

Related exam syllabi

More solved explanations in Arithmetic