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Let A and B be two finite sets such that \(n(A - B)\), \(n(A\cap B)\), \(n(B - A)\) are in an arithmetic progression. Here \(n(X)\) denotes the number of elements in a finite set \(X\). If \(n(A\cup…

Question and options

Let A and B be two finite sets such that n(A−B)n(A - B), n(A∩B)n(A\cap B), n(B−A)n(B - A) are in an arithmetic progression. Here n(X)n(X) denotes the number of elements in a finite set XX. If n(A∪B)=18n(A\cup B) = 18, then n(A)+n(B)n(A) + n(B) is ____
  1. 24
  2. 27
  3. 30
  4. 36

Answer and explanation

Correct answer: A - 24
Let the three counts be x-d, x, x+d. The union is 3x = 18, so the intersection is x = 6. n(A)+n(B) = n(union) + n(intersection) = 18 + 6 = 24.

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