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Kavita's age is eight years more than thrice the sum of the ages of her two grandsons who are twins.…

Let the sum of the twins' present ages be \(S\), so Kavita's age is \(3S+8\). Nine years later \(3S+8+9=2(S+18)+1\), which gives \(S=20\) and Kavita's present age 68. Each…

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Kavita's age is eight years more than thrice the sum of the ages of her two grandsons who are twins. Nine years later, Kavita's age will be one year more than two times the sum of the ages of her two grandsons. What was the age of Kavita when her grandsons were born?

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Correct answer A

Let the sum of the twins' present ages be SS, so Kavita's age is 3S+83S+8. Nine years later 3S+8+9=2(S+18)+13S+8+9=2(S+18)+1, which gives S=20S=20 and Kavita's present age 68. Each twin is 10 now, so when they were born Kavita was 68−10=5868-10=58 years old.

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