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In an isochoric process, we have

Question and options

In an isochoric process, we have
  1. W=0W = 0
  2. Q=0Q = 0
  3. ΔU=0\Delta U = 0
  4. ΔT=0\Delta T = 0

Answer and explanation

Correct answer: A - \(W = 0\)
Isochoric means constant volume, so dV=0\mathrm{d}V = 0 and the work W=∫P dV=0W = \int P\,\mathrm{d}V = 0; Q then equals the change in U.

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