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In a football tournament six teams A, B, C, D, E, and F participated. Every pair of teams had exactly one match among them. For any team, a win fetches 2 points, a draw fetches 1 point, and a loss…

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In a football tournament six teams A, B, C, D, E, and F participated. Every pair of teams had exactly one match among them. For any team, a win fetches 2 points, a draw fetches 1 point, and a loss fetches no points. Both teams E and F ended with less than 5 points. At the end of the tournament points table is as follows (some of the entries are not shown):

Teams Played
 Wins
 Losses
 Draws
 Points
A
 5
 0
 8
B
 5
 2
 6
C
 5
 2
 5
D
 5
 1
 5
E
 5
 1
F
 5


It is known that: (1) team B defeated team C, and (2) team C defeated team D

Total number of matches ending in draw is
  1. 12
  2. 4
  3. 5
  4. 6

Answer and explanation

Correct answer: D - 6
A: 3W 2D; B: 3W 0D 2L; C: 2W 1D 2L; D: 1W 3D 1L; E (4 draws + 1 loss, <5 pts): 0W 4D, 4 pts; F gets 30-28 = 2 pts. B has no draws, so E lost to B and drew A,C,D,F; hence F has a draw, so F = 0W 2D 3L. Draw participations 2+0+1+3+4+2 = 12 -> 6 drawn matches.

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  • IPMAT Indore

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