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In a class, the number of boys is more than number of girls by 10% of the total strength of the class.…

Let the total strength of the class be \(100\). Then \(B + G = 100\) and \(B - G = 10\). Adding the two equations gives \(2B = 110 \implies B = 55\) and \(G = 45\). Thus,…

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In a class, the number of boys is more than number of girls by 10% of the total strength of the class. The ratio of number of boys to girls is –

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Let the total strength of the class be 100100. Then B+G=100B + G = 100 and B−G=10B - G = 10. Adding the two equations gives 2B=110  ⟹  B=552B = 110 \implies B = 55 and G=45G = 45. Thus, B:G=55:45=11:9B : G = 55 : 45 = 11 : 9.

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