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In a class 60% of the students are girls and the rest are boys. Out of these, girls are 30 more than…

Girls (60%) − Boys (40%) = 20% of total = 30, so total students = 150 (90 girls, 60 boys). Total passed = \(68\% \text{ of } 150 = 102\). Since 30 boys passed, \(102 - 30 =…

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In a class 60% of the students are girls and the rest are boys. Out of these, girls are 30 more than the boys. If 68% of the students, including 30 boys, pass an examination, then the percentage of the girls who do not pass the examination is -

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Girls (60%) − Boys (40%) = 20% of total = 30, so total students = 150 (90 girls, 60 boys). Total passed = 68% of 150=10268\% \text{ of } 150 = 102. Since 30 boys passed, 102−30=72102 - 30 = 72 girls passed, and 90−72=1890 - 72 = 18 girls failed. Percentage of girls who failed =1890×100%=20%= \frac{18}{90} \times 100\% = 20\%.

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