In a certain town, 40% of the people have brown hair, 30% have brown eyes and 12% have both brown hair…
42% of the people have neither. The share with brown hair or brown eyes (or both) is 40% + 30% − 12% = 58%, so the rest, 100% − 58% = 42%, have neither. The 12% with both…
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In a certain town, 40% of the people have brown hair, 30% have brown eyes and 12% have both brown hair and brown eyes. What percentage of the people in the town have neither brown hair nor brown eyes?
Answer and explanation
Correct answer D
42% of the people have neither. The share with brown hair or brown eyes (or both) is 40% + 30% − 12% = 58%, so the rest, 100% − 58% = 42%, have neither. The 12% with both features sits inside the 40% and inside the 30%, so it is subtracted once; ignoring the overlap would leave only 30% with neither, and the figures 41%, 43% and 44% do not follow from the data.
Practice for these exams
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Common Management Admission Test (CMAT)