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In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither a red nor a green ball?

Question and options

In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly.
What is the probability that it is neither a red nor a green ball?
  1. 13\frac{1}{3}
  2. 34\frac{3}{4}
  3. 719\frac{7}{19}
  4. 821\frac{8}{21}

Answer and explanation

Correct answer: A - \(\frac{1}{3}\)
Neither red nor green means blue: 7 blue out of 21 balls, probability 721=13\frac{7}{21} = \frac{1}{3}.

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  • CUSAT CAT LLM

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