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If the ratio of ages of Seema and Reema is 9 : 16, after ten year it will be 2 : 3. The ratio of ages…

Let the present ages of Seema and Reema be \(9x\) and \(16x\). After 10 years: \(\frac{9x + 10}{16x + 10} = \frac{2}{3} \implies 27x + 30 = 32x + 20 \implies 5x = 10…

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If the ratio of ages of Seema and Reema is 9 : 16, after ten year it will be 2 : 3. The ratio of ages of Seema and Reema before six years was :

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Correct answer D

Let the present ages of Seema and Reema be 9x9x and 16x16x. After 10 years: 9x+1016x+10=23  ⟹  27x+30=32x+20  ⟹  5x=10  ⟹  x=2\frac{9x + 10}{16x + 10} = \frac{2}{3} \implies 27x + 30 = 32x + 20 \implies 5x = 10 \implies x = 2. Their present ages are 1818 and 3232 years. Six years ago, the ratio of their ages was 18−632−6=1226=613\frac{18 - 6}{32 - 6} = \frac{12}{26} = \frac{6}{13}, i.e., 6:136 : 13.

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