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If the radius of the nucleus is of the order of \(10^{-13}\) cm and the mass of the nucleus is of the order of \(10^{-24}\) gm, then the density of the nuclear matter is of the order of

Question and options

If the radius of the nucleus is of the order of 10−1310^{-13} cm and the mass of the nucleus is of the order of 10−2410^{-24} gm, then the density of the nuclear matter is of the order of
  1. 10810^{8} gm/cc
  2. 102010^{20} gm/cc
  3. 101410^{14} gm/cc
  4. 101210^{12} gm/cc

Answer and explanation

Correct answer: C - \(10^{14}\) gm/cc
Volume =43π(10−13)3≈4×10−39= \frac{4}{3}\pi (10^{-13})^3 \approx 4 \times 10^{-39} cc; density =10−24/(4×10−39)≈2.4×1014= 10^{-24}/(4 \times 10^{-39}) \approx 2.4 \times 10^{14} g/cc, of order 101410^{14}.

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