If the mean of \(a\), \(b\), and \(c\) is \(M\); \(ab + bc + ca = 0\); and the mean of \(a^2\), \(b^2\) and \(c^2\) is \(KM^2\), then \(K\) is equal to
Question and options
If the mean of , , and is ; ; and the mean of , and is , then is equal to
- 3
- 9
- 6
- 4
Answer and explanation
Correct answer: A - 3
a^2+b^2+c^2 = (a+b+c)^2 - 2(ab+bc+ca) = (3M)^2 = 9M^2. Mean = 3M^2, so K = 3.
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