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If the mean of \(a\), \(b\), and \(c\) is \(M\); \(ab + bc + ca = 0\); and the mean of \(a^2\), \(b^2\) and \(c^2\) is \(KM^2\), then \(K\) is equal to

Question and options

If the mean of aa, bb, and cc is MM; ab+bc+ca=0ab + bc + ca = 0; and the mean of a2a^2, b2b^2 and c2c^2 is KM2KM^2, then KK is equal to
  1. 3
  2. 9
  3. 6
  4. 4

Answer and explanation

Correct answer: A - 3
a^2+b^2+c^2 = (a+b+c)^2 - 2(ab+bc+ca) = (3M)^2 = 9M^2. Mean = 3M^2, so K = 3.

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