If the harmonic mean of the roots of the equation \((5 + \sqrt{2}) x ^ 2 - bx + 8 + 2\sqrt{5} = 0\) is \(4\) then the value of \(b\) is
Question and options
If the harmonic mean of the roots of the equation is then the value of is
Answer and explanation
Correct answer: D - \(4+\sqrt{5}\)
HM of roots = 2*(product)/(sum) = 2*(c/a)/(b/a) = 2c/b = 4, so b = c/2 = (8+2sqrt5)/2 = 4+sqrt5 (the leading coefficient cancels).
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