If the average of 10 numbers is 40 and the average of six of them is 28, then the average of the…
The ten numbers total \(10 \times 40 = 400\) and the six numbers total \(6 \times 28 = 168\). The remaining four therefore total 400 − 168 = 232. Their average is 232 ÷ 4 =…
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If the average of 10 numbers is 40 and the average of six of them is 28, then the average of the remaining four numbers is:
Answer and explanation
Correct answer D
The ten numbers total and the six numbers total . The remaining four therefore total 400 − 168 = 232. Their average is 232 ÷ 4 = 58.
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