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If \(sin \theta + cos \theta = m\), then \(sin^6 \theta + cos^6 \theta\) equals

Question and options

If sinθ+cosθ=msin \theta + cos \theta = m, then sin6θ+cos6θsin^6 \theta + cos^6 \theta equals
  1. 3(m2+1)4\frac{3(m^2+1)}{4}
  2. 3(m2−1)4\frac{3(m^2-1)}{4}
  3. 1−3(m2−1)41-\frac{3(m^2-1)}{4}
  4. 1−3(m2−1)241-\frac{3(m^2-1)^2}{4}

Answer and explanation

Correct answer: D - \(1-\frac{3(m^2-1)^2}{4}\)
sin^6 + cos^6 = 1 - 3 sin^2 cos^2, and sin*cos = (m^2-1)/2, so value = 1 - 3(m^2-1)^2/4.

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  • IPMAT Indore

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