Site navigation

If \(\dfrac{a}{b+c}=\dfrac{b}{c+a}=\dfrac{c}{a+b}=k\) then value of \(k\) is

Question and options

If ab+c=bc+a=ca+b=k\dfrac{a}{b+c}=\dfrac{b}{c+a}=\dfrac{c}{a+b}=k then value of kk is
  1. ±12\pm \frac{1}{2}
  2. 12\frac{1}{2} or −1-1
  3. −1-1
  4. 12\frac{1}{2}

Answer and explanation

Correct answer: B - \(\frac{1}{2}\) or \(-1\)
Adding the numerators and denominators gives k = (a+b+c)/(2(a+b+c)) = 1/2 if a+b+c is not 0. If a+b+c = 0, then b+c = -a and k = -1. So k = 1/2 or -1.

Practice for these exams

  • JIPMAT

Related question papers

Related exam syllabi

More solved explanations in Number series & simplification