If 5 boys and 3 girls sit randomly around a circular table, the probability that there will be at least one boy sitting between any two girls is
Question and options
If 5 boys and 3 girls sit randomly around a circular table, the probability that there will be at least one boy sitting between any two girls is
Answer and explanation
Correct answer: B - \(\frac{2}{7}\)
Total circular arrangements 7! = 5040. Seat boys in 4! = 24 ways, place 3 girls in 3 of the 5 gaps: 5P3 = 60. Favourable 1440, probability 1440/5040 = 2/7.
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