Site navigation

If \(2^{x+y} = 4^{x-y} = \sqrt{32}\), then \(xy = \) ___.

Question and options

If 2x+y=4x−y=322^{x+y} = 4^{x-y} = \sqrt{32}, then xy=xy = ___.
  1. 7532\frac{75}{32}
  2. 7564\frac{75}{64}
  3. 7516\frac{75}{16}
  4. 75128\frac{75}{128}

Answer and explanation

Correct answer: B - \(\frac{75}{64}\)
sqrt(32) = 2^(5/2). So x + y = 5/2 and 2(x - y) = 5/2, giving x - y = 5/4. Then x = 15/8, y = 5/8, xy = 75/64.

Practice for these exams

  • IIM Bangalore BBA DBE Entrance Test

Related question papers

Related exam syllabi

More solved explanations in Arithmetic