Given \(f(x) = x^2 + \log_3 x\) and \(g(y) = 2y + f(y)\), then the value of \(g(3)\) equals

First f(3) = 3 squared + log base 3 of 3 = 9 + 1 = 10. Then g(3) = 2 x 3 + f(3) = 6 + 10 = 16. The value 15 comes from forgetting that log base 3 of 3 equals 1, not 0.