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For some non-zero real values of \(a, b\) and \(c\), it is given that \(\left|\frac{c}{a}\right|=4,\left|\frac{a}{b}\right|=\frac{1}{3}\) and \(\frac{b}{c}=-\frac{3}{4}\). If \(a c>0\), then…

Question and options

For some non-zero real values of a,ba, b and cc, it is given that ∣ca∣=4,∣ab∣=13\left|\frac{c}{a}\right|=4,\left|\frac{a}{b}\right|=\frac{1}{3} and bc=−34\frac{b}{c}=-\frac{3}{4}. If ac>0a c>0, then (b+ca)\left(\frac{b+c}{a}\right) equals
  1. 1
  2. -1
  3. 7
  4. -7

Answer and explanation

Correct answer: A - 1
ac>0 so c/a=4, c=4a; b=-(3/4)c=-3a (consistent with |a/b|=1/3). (b+c)/a = (-3a+4a)/a = 1.

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