Find the area of the sector of a circle of radius 14 cm and angle of sector is \(45^\circ\)

The area of a sector is $\frac{\theta}{360^\circ}\times\pi r^2$. Here $\frac{45}{360}=\frac18$ and $\pi r^2=\frac{22}{7}\times14\times14=616$ cm$^2$, so the area is $\frac18\times616=77$ cm$^2$. 616 cm$^2$ is the whole circle, and a $45^\circ$ sector is only one-eighth of it.