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Find the area (in square units) bounded by \(x=6, y=0, 3x-2y=0\), and \(x-4y+10=0\).

Question and options

Find the area (in square units) bounded by x=6,y=0,3x−2y=0x=6, y=0, 3x-2y=0, and x−4y+10=0x-4y+10=0.
  1. 34
  2. 31
  3. 15
  4. 17

Answer and explanation

Correct answer: D - 17
Lines y=1.5x and y=(x+10)/4 meet at (2,3). Region vertices: (0,0), (6,0), (6,4), (2,3). Shoelace: (0 + 24 + 10 + 0)/2 = 17.

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